H=-1.6t^2+2

Solution for H=-1.6t^2+2 equation:

=-1.6H^2+2

We move all terms to the left:

-(-1.6H^2+2)=0

We get rid of parentheses

1.6H^2-2=0

a = 1.6; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·1.6·(-2)
Δ = 12.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{12.8}}{2*1.6}=\frac{0-\sqrt{12.8}}{3.2}
=-\frac{\sqrt{}}{3.2}
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{12.8}}{2*1.6}=\frac{0+\sqrt{12.8}}{3.2}
=\frac{\sqrt{}}{3.2}
$